Question 1. A Project Manager Estimated That He Would Complete The Project In Time If He Hires 42 People For 38 Days. At The End Of 30 Days He Realized That Only three/fifth Of The Work Is Complete. How Many More Men Does He Need To Hire To Complete The Work In Time ?

Answer :

42 humans in 30 days did three/fifth of the work

Let x human beings are required to complete the final 2/fifth of the work in 8 days

Applying chain rule we get x = 42 × 30/eight × (2×five)/(three×5) = 105 humans

Additional no. Of people required = ( 105 - forty two ) = sixty three.

Question 2. Pipe A Can Fill A Tank In 8 Hours And Pipe B Can Fill It In 6 Hours. If Both The Pipes Are Opened But After 2 Hours Pipe A Is Closed, Then The Other Pipe Will Fill The Tank In ?

Answer :

Tank part filled by way of Pipe A in 1 hour = 1/8

or

Time taken to fill 1/8 part of tank filled A = 1 hour ------------- (1)

Tank component crammed with the aid of Pipe B in 1 hours = 1/6

or

Time taken to fill 1/6 part of tank stuffed B = 1 hour ---------(2)

=> Tank Part crammed through (A+B) in 1 hour = (1/eight + 1/6)

=> Tank Part crammed via (A+B) in 2 hour = 2*(1/eight + 1/6) = 2*(three+four)/24 = 2*7/24 = 7/12

After 2 hours left over portion of tank = (1-7/12) = five/12

Time taken to fill 1/6 part of tank filled B = 1 hour

so time taken to fill five/12 a part of tank through B = 6 * 5/12 = 5/2 = 2 half

=> So it takes 2 1/2 hrs (2hrs 30 min) to fill five/12 of tank.

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Question three. On Selling 17 Balls At Rs. 720, There Is A Loss Equal To The Cost Price Of five Balls. The Cost Price Of A Ball Is ?

Answer :

(C.P. Of 17 balls) - (S.P. Of 17 balls) = (C.P. Of five balls)

Question four. A Man Pointing To A Photograph Says, The Lady In The Photograph Is My Nephew's Maternal Grandmother. How Is The Lady In The Photograph Related To The Man's Sister Who Has No Other Sister ?

Answer :

Clearly, the lady is the grandmother of man's sister's son.

I.E., the mom of the mom of man's sister's son.

=> The mother of man's sister.

So, the female is guy's mother.

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Question 5. Pointing To A Lady A Person Said, "the Son Of Her Only Brother Is The Brother Of My Wife." How Is The Lady Related To The Person ?

Answer :

Brother of person's wife brother-in-law of the character. Hence, the son of woman's brother is brother-in-law of the man or woman.

Therefore, the brother of the woman is the father-in-regulation of the person. Hence, the girl is the sister of the man or woman's father-in-regulation.

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Question 6. If 378 Coins Consist Of Rupee, 50 Paise And 25 Paise Coins, Whose Values Are Proportional To thirteen :11 : 7, The Number Of 50 Paise Coins Will Be ?

Answer :

If values are proportional to thirteen : 11 : 7, then the number of cash may be proportional to thirteen/1 : eleven/zero.50 : 7/zero.25 ⇒ 13 : 22 : 28.

Now from this the quantity of coins of fifty paise may be 378 × 22/sixty three = 132.

Question 7. Simplify (0.001344 / zero.Three X zero.7) = ?

Answer :

(zero.001344 / zero.Three x 0.7) = zero.0064

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Question eight. The Difference Of Two Numbers Is eleven And One Fifth Of Their Sum Is 9. The Numbers Are ?

Answer :

x − y = eleven, x + y = 5 × 9 x − y = eleven, x + y = forty five, y = 17, x = 28

Question nine. If A, B, C, D, E Are Five Consecutive Odd Numbers, Their Average Is ?

Answer :

b = a + 2

c = b + 2 = a + four

d = c + 2 = a + 6

e = d + 2 = a + 8

Therefore, Required common = (a + a + 2 + a + 4 + a + 6 + a + 8)/5

= a + 4

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Question 10. The Average Of 20 Numbers Is 15 And The Average Of First Five Is 12. The Average Of The Rest Is ?

Answer :

If the common of last numbers be x, then

20 × 15 = five × 12 + 15x

⇒ 300 = 60 + 15x

⇒ 15x = three hundred – 60 = 240

=> x = 240/15 = sixteen

Question eleven. What Is The Next Number Of The Following Sequence 125102550(?).

Answer :

Consider the series as 1 2 five 10 25 50 ____

1*2 = 2

2*2.Five = five

5*2 = 10

10*2.Five = 25

25*2 = 50

50*2.Five = 125

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Question 12. If The Value Of The Numerator Is Increased By 20% And That Of The Denominator Is Decreased By 25% The Fraction Becomes Unity The Numerator Of Original Fraction Is ?

Answer :

120n/75d=1

n/d=75/a hundred and twenty=five/8

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Question thirteen. A Started Business Investing Rs. 60,000.Exactly Six Months Later,b Joined Him Investing Rs. Ninety,000.If They Make A Profit Of Rs. 1,26,000 At The End Of The Year. How Much Should B's Share In It ?

Answer :

A investment for twelve months = 60,000*12 = 720000

B funding for 6 months = 90000 * 6 = 540000

A & B investment ratio = 72/54 => 4/three

So, B' proportion = 126000 * 3/7= 54000

Question 14. B's Monthly Salary Is Less By 10% Than That Of A's.C's Monthly Salary Is Less By 25% Than That Of A's.Through What Percent Of B's Salary More Than That Of C's ?

Answer :

Lets don't forget c's income = Rs. A hundred

B's can be ninety

C's may be one hundred(1-25/a hundred)=100*(seventy five/one hundred)=seventy five

[(90-75)/75]*one hundred=(15/seventy five)*100=20%

Question 15. Sand And Cement Were Mixed In The Ratio 3 : 1 To Make Up 1 Tonne. How Much Sand Must Be Added To Make The Ratio 6 : 1 ?

Answer :

Let amount of sand and cement as 3x and x

3x+x = 1000kg

x = 250

Sand : cement => 750 : 250

(750+y)/250 = 6/1

=> y = 750 kg.

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Question sixteen. Five Years Ago The Average Age Of A Family Of Six Members Was 20 Years. A Baby Is Born And Now The Average Age Is 22 Years. How Old Is The Baby At Present ?

Answer :

Lets expect the age of all the 6 human beings = 20 years.

After 5 years i.E. Now their a while could be 25 years.

Total age of all the 6 might be = 25*6 = one hundred fifty

Including infant's age, avg is 22 years

Let x be the age of toddler.

(one hundred fifty+x)/7 = 22

=> x = four years.

Question 17. Two Trains 246 M And 304 M Long Are Travelling Towards One Another At 114 Km/hr And sixty six Km/hr Respectively. How Long Do The Trains Take To Pass One Another ?

Answer :

114 km/h => 114*five/18 m/s => 95/three m/s

66km/h => sixty six*five/18 m/s => 55/3 m/s

Time taken = (246+304)/(fifty five/three + ninety five/three) => 11 sec

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Question 18. The Mean Daily Profit Made By A Shopkeeper In A Month Of 30 Days Was Rs. 350. If The Mean Profit For The First Fifteen Days Was Rs. 275, Then The Mean Profit For The Last 15 Days Would Be ?

Answer :

Average would be : 350 = (275 + x)/2

On solving, x = 425.

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Question 19. There Were 35 Students In A Hostel. If The Number Of Students Increases By 7, The Expenses Of The Mess Increase By Rs. Forty two Per Day While The Average Expenditure Per Head Diminishes By Re 1. Find The Original Expenditure Of The Mess?

Answer :

Let d be the average each day expenditure

Original expenditure = 35 × d

New expenditure = 35 × d + forty two

New average expenditure might be :

(35 × d + forty two)/forty two = d - 1

On fixing, we get d = 12

Therefore original expenditure = 35 × 12 = 420

Question 20. The Ratio Between The Number Of Passengers Travelling By I And Ii Class Between The Two Railway Stations Is 1 : 50, Whereas The Ratio Of I And Ii Class Fares Between The Same Stations Is 3 : 1. If On A Particular Day Rs. 1,325 Were Collected From The Passengers Travelling Between These Stations, Then What Was The Amount Collected From The Ii Class Passengers ?

Answer :

Let x be the wide variety of passengers and y be the fare taken from passengers.

3xy + 50xy = 1325 => xy = 25

Amount gathered from II magnificence passengers = 25 × 50 = Rs. 1250.

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Question 21. A Boat Travels Upstream From B To A And Downstream From A To B In three Hours. If The Speed Of The Boat In Still Water Is 9 Km/hour And The Speed Of The Current Is 3 Km/hour, The Distance Between A And B Is ?

Answer :

Let d be the gap between A and B

So, d/12 + d/6 = three d = 12 km

Question 22. The Fuel Indicator In A Car Shows 1/fifth Of The Fuel Tank As Full. When 22 More Liters Of Fuel Are Poured In To The Tank, The Indicator Rests At The 3/4of The Full Mark. Find The Capacity Of The Tank ?

Answer :

x/5 + 22 = 3x/4 ⇒ x = forty litres

Question 23. In A Kilometer Race, A Can Give B A 100 M Start And C A a hundred and fifty M Start. How Many Meters Start Can B Give To C ?

Answer :

A can supply B a 100 m begin and C a 150m. Start means when A runs 1000m, B runs 900m and C runs 850m.

When B runs 1000m, C will run one thousand x (850/900) m (i.E. 8500/9 m)

Thus, B can provide C a start of - 1000 - (8500/nine), i.E. 500/9 m.

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Question 24. The Average Age Of All The Student Of A Class Is 18 Years. The Average Age Of Boys Of The Class Is 20 Years And That Of The Girls Is 15 Years. If The Number Of Girls In The Class Is 20, Then Find The Number Of Boys In The Class ?

Answer :

Let Boys in class = B

Girls in elegance = 20

Now, (20B+15*20)/(B+20) = 18

⇒ B = 30

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Question 25. A Clock Showed five Min Past 3'0 Clock On Sunday Evening When The Correct Time Was 3'zero Clock It Looses Uniformly And Was Observed To Be 10 Min Slow On The Subsequent Tuesday At 9pm . When Did The Clock Show The Correct Time?

Answer :

Clock confirmed 5 min past three'0 clock on Sunday night when the perfect time became three'0 clock.

It looses uniformly and turned into determined to be 10 min sluggish on the following Tuesday at 9pm .

In 54 hrs , it lost 15 mins.

So five minutes are lost in five*54/15 = 18 hrs

so watch showed accurate time at 1500+1800-2400= 0900 hrs on Monday i.E 9AM Monday

Question 26. A Jar Was Containing 60 Liters Of Mixture Of Milk And Water In The Ratio 7:five. From This Jar 12 Litres Of Mixtures Was Taken Out And eight Litres Of Pure Milk Was Added. What Is The Respective Ratio Of Milk And Water In The Mixture After The Final Operation ?

Answer :

Let n be the mixture quantity of milk = 7/12 × 60 Ltr = 35 Ltr

Quantity of water = five/12 × 60 Ltr. = 25 Ltr

12 Ltr. Of mixture removed includes milk = 7/12 × 12 Ltr. = 7 Ltr and water = 5/12 × 12 Ltr = five Ltr

After including 8 Ltr of pure milk,

Net milk in the aggregate = 35 - 7 + 8 = 36 Ltr.

Net water inside the aggregate = 25 - 5 = 20 Ltr.

So the specified ratio of milk and water now = 36/20 = 9/5

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Question 27. A Bath Tub Can Be Filled By A Cold Water Pipe In 20 Minutes And By A Hot Water Pipe In 30 Minutes. A Person Leaves The Bathroom After Turning On Both Pipes Simultaneously And Returns At The Moment When The Bath Tub Should Be Full. Finding However, That The Waste Pipe Has Been Open, He Now Closes It. In three Minutes More The Bath Tub Is Full. In What Time Would The Waste Pipe Empty It ?

Answer :

Total paintings = 1/20 + 1/30

(3+2)/60 = 5/60 = 1/12

For each of them wished = 12 min.

But because of leakage it take = 15 min.

So we can say for filling pipe it takes 3 minutes

work for the waste pipe may be = 12 min.

3 min. Of each filling pipe = 12 min. Of waste pipe

12 min. Of filling pipe may be = forty eight min. Of waste pipe i.E.

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