Question 1. A Boy Is Running At A Speed Of P Km/hr To Cover A Distance Of 1km But Due To The Slippery Ground, His Speed Is Reduced By Q Km/hr(p>q).If The Takes R Hours To Cover The Distance Then?

Answer :

Actual speed = (P-Q)km/hr , time taken =R hrs

Distance =(Speed x time)

Therefore, 1 =(P-Q)R => 1/R =(P-Q).

Question 2. Sunil Covers A Distance By Walking For 6 Hours While Returning His Speed Decreases By 1km/hr And He Takes nine Hours To Covers The Same Distance What Was His Speed In Turns Journey?

Answer :

Let the rate in go back journey be x km/hr, then

6(x +1) =9x

=> 3x =6

=> x =2

Hence the velocity in return journey is 2km/hr.

Aptitude Interview Questions

Question three. A Takes 2 Hours More Than B To Walk D Km. If A Doubles His Speed Then He Can Make It In 1 Hour Less Than B. How Much Time Does B Require For Walking D Km?

Answer :

Suppose B takes x hours to stroll d km

Then A takes (x+2) hours to stroll d km

With double of the speed.

A will take ½(x+2)hours

Therefore, x -half of(x+2) = 1

2x –(x+2)

X =four

Hence B takes four hours to stroll d km.

Question 4. 12 Men Or 18 Women Can Reap A Field In 14 Days. The Number Of Days That eight Men And sixteen Women Will Take To Reap It?

Answer :

12 men = 18 girls or 1 guy = 3/2 ladies

Therefore eight guys + sixteen ladies = (eight × 3/2 + 16) girls i.E.., 28 ladies

Now 18 ladies can gain the sphere in 14 days

Therefore, 28 women can gain it in = 9 days.

Question five. If three Men Or 4 Women Can Construct A Wall In forty three Days, Then The Number Of Days That 7 Men And five Women Take To Construct It Is?

Answer :

3 guys = 4 ladies or 1 man = 4/3 girls

Therefore 7 guys + five ladies = (7 × four/3 + five)women i.E.., 43/three women

4 women can assemble the wall in 43 days

Therefore, 43/three girls can construct it in = 12 days.

ABB Group Aptitude Interview Questions

Question 6. 10 Men Can Finish A Piece Of Work In 10 Days. Whereas It Takes 12 Women To Finish It In 10 Days If 15 Men And 6 Women Undertake To Complete The Work. How Many Days Will They Take To Complete It?

Answer :

10 guys = 12 girls or 1 man = 6/5 girls

Therefore 15 men + 6 ladies = (15 x 6/5 +6)ladies i.E,, 24 girls

Now 12 girls can do the work in 10 days

Therefore, 24 ladies can do it in = five days.

Question 7. Eight Children And 12 Men Complete A Certain Piece Of Work In nine Days. If Each Child Takes Twice The Time Taken By Man To Finish The Work. In How Many Days Will 12 Men Finish The Same Work?

Answer :

2 kids = 1 man

Therefore (eight children +12 guys) = sixteen guys

Now less guys more days 12: 16 : : nine : x

Therefore, x = (one hundred forty four/12) = 12 days.

Abaxis Aptitude Interview Questions

Question 8. If 10% Of X = 20% Of Y, Then X:y Is Equal To?

Answer :

10% of x = 20% of y

10x/a hundred = 20y/100 => x/10 = y/five

x/y = 10/five = 2/1

x:y = 2:1.

Question nine. The Ratio Of The Number Of Boys And Girls In A College Is 7:eight. If The Percentage Increase In The Number Of Boys And Girls Be 20% And 10% Respectively. What Will Be The New Ratio?

Answer :

Originally, allow the range of boys and girls inside the college be 7x and 8x respectively.

Their extended number is (120% of 7x) and (110% of 8x).

I.E., (120/a hundred * 7x) and (one hundred ten/a hundred * 8x)

i.E., 42x/5 and 44x/5

Required ratio = 42x/5 : 44x/5 = 21:22.

Yahoo Aptitude Interview Questions

Question 10. If forty% Of A Number Is Equal To Two-1/3 Of Another Number, What Is The Ratio Of First Number To The Second Number?

Answer :

Let 40% of A = 2/3 B. Then,

40A/a hundred = 2B/3 => 2A/5 = 2B/three

A/B = (2/3 * five/2) = five/three

A:B = 5:three.

Question eleven. Ratio Of The Earnings Of A And B Is four:7. If The Earnings Of A Increases By 50% And Those Of B Decreased By 25%, The New Ratio Of Their Earnings Becomes 8:7. What Are A's Earnings?

Answer :

Let the authentic earnings of A and B be Rs. 4x and Rs. 7x.

New income of A = 150% 0f Rs. 4x = (one hundred fifty/100 * 4x) = Rs. 6x

New profits of B = 75% of Rs. 7x = (seventy five/a hundred * 7x) = Rs. 21x/4

6x:21x/four = eight:7

This does no longer deliver x. So, the given data is inadequate.

SAP Aptitude Interview Questions

Question 12. On A Certain Sum, The Simple Interest At The End Of 12 ½ Years Becomes ¾ Of The Sum. What Is The Rate Percent Per Annum?

Answer :

Let the sum be Rs x.

Then S.I = Rs 3x/four, Time = 25/2 Years

Therefore, Rate = (100 × 3x/four × 1/x × 2/25) % p.A

= 6 % p.A.

Aptitude Interview Questions

Question thirteen. Rs.One thousand Is Invested At five % P.A Simple Interest If The Interest Is Added To The Principle After Every 10 Years. The Amount Will Become Rs. 2000 After?

Answer :

S. I for 10 Years = Rs (a thousand × five/one hundred × 10) = Rs 500

Principle after 10 Years becomes = Rs (one thousand + 500)

= Rs 1500

S. I on it = Rs (2000 - 1500) = Rs 500

Time = (50000/7500) Years = 6 2/three Years

Total Time = (10 + 6 2/3) Years = 16 2/3 Years.

Question 14. The Average Of Women And Child Workers In A Factory Was 15%12 months. The Average Age Of All The 16 Children Was 8yr And Average Age Of Women Workers Was 22 Yrs If Ten Women Workers Were Married Then The Number Of Unmarried Women Workers Were?

Answer :

Let the variety of ladies workers be x

According to the question 22*x+sixteen*eight = 15(sixteen+x)

=> 22x+128 =240 +15x

=> 22x-15x = 240 -128

=> 7x=112

Therefore, x=112/7 =sixteen

Therefore, Unmarried ladies workers =(16-10) =6.

Question 15. A Person Travels From X To Y At A Speed Of 40km/h And Returns By Increasing His Speed 50%. What Is His Average Speed For Both The Trips?

Answer :

Speed of individual from x to y =40 km/h

Speed of man or woman from y to x =(40x150)/a hundred = 60km/h

Since the distance travelled is same

Therefore, Average Speed = (2x40x60)/forty+60 = 48km/h.

Oracle Aptitude Interview Questions

Question sixteen. The Average Of 18 Observations Was Calculated And It Was 124. Later On It Was Discovered That Two Observations forty six And eighty two Were Incorrect. The Correct Values Are sixty four And 28. The Correct Average Of 18 Observations Is?

Answer :

Sum of 18 observations = 18x124 =2232

Correct sum of 18 observations = 2232-46-eighty two+sixty four+28

= 2196

Therefore, Correct average =2196/18 = 122.

Question 17. Three Taps A, B And C Can Fill A Tank In 12, 15 And 20 Hours Respectively. If A Is Open All The Time And B And C Are Open For One Hour Each Alternately, The Tank Will Be Full Is?

Answer :

(A + B)'s 1 hour paintings = (1/12 + 1/15) = 3/20

(A + C)'s 1 hour work = (1/12 + 1/20) = 2/15

Part stuffed in 2 hrs = (three/20 + 2/15) = 17/60

Part filled in 6 hrs = three * 17/60 = 17/20

Remaining part = 1 - 17/20 = three/20

Now, it is the flip of A and B and 3/20 element is stuffed through A and B in 1 hour.

Total time taken to fill the tank = (6 + 1) = 7 hrs.

BHEL Aptitude Interview Questions

Question 18. A Thief Steals A Ca R At 2.30 Pm And Drives It At 60 Kmph.The Theft Is Discovered At 3 Pm And The Owner Sets Off In Another Car At 75 Kmph When Will He Overtake The Thief?

Answer :

Let the thief is overtaken x hrs after 2.30 pm

distance included by means of the thief in x hrs = distance protected by using

the proprietor in x-half of hr

60x = 75 ( x- ½)

x= five/2 hr

thief is overtaken at 2.30 pm + 2 ½ hr = five pm.

ABB Group Aptitude Interview Questions

Question 19. A Top Can Fill A Cistern In eight Hours And Another Can Empty It In 16 Hours. If Both The Taps Are Opened Simultaneously The Time (in Hours) To Fill The Tank Is?

Answer :

Part crammed by way of insert in 1 hour = 1/8

Part emptied by using outlet in 1 hour = 1/sixteen

Net filling in 1 hour = (1/eight - 1/16) = 1/sixteen

Time taken to fill the tank = 1/16 hour= 16 hours.

Question 20. The Difference Between Simple And Compound Interest (compounded-annually) On A Sum Of Money For 2 Years At 10% Per Annum Is Rs sixty five. The Sum Is?

Answer :

Let the sum be Rs x.

Then [x × (1 +10/100)2 - x] – (x × 10/a hundred × 2) = 65

=> (x × eleven/10 × eleven/10 - x) – x/five = sixty five

=> (121x/100 - x) – x/5 = sixty five

=> (21x/100 – x/five) = sixty five

=> (21x – 20x) = 6500

=> X = 6500.

TCS Aptitude Interview Questions

Question 21. The Effective Annual Rate Of Interest Corresponding To A Nominal Rate Of 6% Per Annum Payable Half Yearly Is?

Answer :

Let the sum be Rs one hundred.

Then P = Rs a hundred, R = 3 %

per half – 12 months, t = 2 1/2 – years

Amount = Rs [100 × (1 + 3/100)2]

= Rs (one hundred × 103/100 × 103/one hundred)

= Rs 10609/100 = Rs 106.09

Effective Annual Rate = 6.09%.

Question 22. A Dealer Marks His Goods 20% Above Cost Price. He Then Allows Some Discount On It And Makes A Profit Of eight%. The Rate Of Discount Is?

Answer :

C.P = Rs. One hundred

Marked Price = Rs. 120,

S.P = Rs. 108

Discount = (12/120 × one hundred)% = 10%.

Question 23. Tarun Bought A T.V With 20% Discount On The Labelled Price. Had He Bought It With 25% Discount? He Would Have Saved Rs. 500. At What Price Did He Buy The T.V?

Answer :

Labelled rate be Rs. 100

S.P in 1st case = Rs. Eighty

S.P in 2d case = Rs. Seventy five

Saving is Rs. Five labelled price = Rs. 100

Saving is Rs. 500 labelled charge

= Rs. (a hundred/5 × 500) = Rs. 10000.

Capgemini Aptitude Interview Questions

Question 24. The Difference Between A Discount Of forty% On Rs. 500 And Two Successive Discount Of 36% And 4% On The Same Amount Is?

Answer :

Sale after forty% bargain = 60% of Rs. 500 = Rs. Three hundred

Price after 36% bargain = 64% of Rs. 500 = Rs. 320

Price after subsequent four% cut price = 96% of Rs. 320 = Rs. 307.20

Difference in two fees = Rs. 7.20.

Abaxis Aptitude Interview Questions

Question 25. A Cloth Merchant Has Announced 25% Rebate In Prices. If One Needs To Have A Rebate Of Rs. Forty. Then How Many Shirts Each Costing Rs.32 He Should Purchase?

Answer :

The variety of shirts = X

Rebate = (25/one hundred × 32 X) = 8X

8X = forty or X = five.

Question 26. Two Vessels P And Q Contain 62.Five% And 87.5% Of Alcohol Respectively. If 2 Litres From Vessel P Is Mixed With 4 Litres From Vessel Q, The Ratio Of Alcohol And Water In The Resulting Mixture Is?

Answer :

Quantity of alcohol in vessel P = 62.5/one hundred * 2 = five/four litres

Quantity of alcohol in vessel Q = 87.Five/one hundred * four = 7/2 litres

Quantity of alcohol in the aggregate formed = five/4 + 7/2 = 19/four = 4.75 litres

As 6 litres of aggregate is fashioned, ratio of alcohol and water within the aggregate formed = 4.Seventy five : 1.25 = 19 : five.

Cognizant Aptitude Interview Questions

Question 27. A Vessel Of Capacity 90 Litres Is Fully Filled With Pure Milk. Nine Litres Of Milk Is Removed From The Vessel And Replaced With Water. Nine Litres Of The Solution Thus Formed Is Removed And Replaced With Water. Find The Quantity Of Pure Milk In The Final Milk Solution?

Answer :

Let the preliminary amount of milk in vessel be T litres.

Let us say y litres of the mixture is taken out and changed by water for n instances, alternatively.

Quantity of milk eventually inside the vessel is then given by means of [(T - y)/T]n * T

For the given trouble, T = ninety, y = nine and n = 2.

Hence, quantity of milk finally in the vessel

= [(90 - 9)/90]2 (ninety) = 72.Nine litres.

Yahoo Aptitude Interview Questions

Question 28. Ajay And Vijay Have Some Marbles With Them. Ajay Told Vijay "if You Give Me 'x' Marbles, Both Of Us Will Have Equal Number Of Marbles". Vijay Then Told Ajay "if You Give Me Twice As Many Marbles, I Will Have 30 More Marbles Than You Would". Find 'x'?

Answer :

If Vijay gives 'x' marbles to Ajay then Vijay and Ajay would have V - x and A + x marbles.

V - x = A + x --- (1)

If Ajay gives 2x marbles to Vijay then Ajay and Vijay would have A - 2x and V + 2x marbles.

V + 2x - (A - 2x) = 30 => V - A + 4x = 30 --- (2)

From (1) we've V - A = 2x

Substituting V - A = 2x in (2)

6x = 30 => x = five.

Question 29. A Man Traveled A Total Distance Of 1800 Km. He Traveled One-0.33 Of The Whole Trip By Plane And The Distance Traveled By Train Is Three-5th Of The Distance Traveled By Bus. If He Traveled By Train, Plane And Bus, Then Find The Distance Traveled By Bus?

Answer :

Total distance traveled = 1800 km.

Distance traveled with the aid of aircraft = 600 km.

Distance traveled by using bus = x

Distance traveled by using teach = 3x/5

=> x + 3x/five + 600 = 1800

=> 8x/five = 1200 => x = 750 km.

Question 30. The Bus Fare For Two Persons For Travelling Between Agra And Aligarh Id Four-thirds The Train Fare Between The Same Places For One Person. The Total Fare Paid By 6 Persons Travelling By Bus And eight Persons Travelling By Train Between The Two Places Is Rs.1512. Find The Train Fare Between The Two Places For One Person?

Answer :

Let the educate fare among the 2 locations for one man or woman be Rs.T

Bus fare between the 2 places for two individuals Rs.Four/3 t

=> 6/2 (4/three t) + eight(t) = 1512

=> 12t = 1512 => t = 126.

Question 31. If X = V196 + V200, Then X/2 + 2/x Is?

Answer :

x = 14 + 10v2

x/2 = 7 + 5v2

2/x = (7 - 5v2) / (7 + 5v2)(7 - 5v2) = 5v2 - 7

x/2 + 2/x = 10v2 = 2v50.

Question 32. There Are Two Identical Red, Two Identical Black, And Two Identical White Balls.In How Many Different Ways Can The Balls Be Placed In The Cells (each Cell To Contain One Ball) Shown Above Such That Balls Of The Same Colour Do Not Occupy Any Two Consecutive Cells?

Answer :

Case I : 2 balls of the same coloration and balls are a specific coloration are organized.

Two balls of the same shade and balls of different colorings may be arranged collectively wherein balls of the identical shade are adjacent =four!/2!X2! = 6 approaches

Therefore, Total number of preparations = 6x3 =18 approaches

Case II : Two shades out of 3 may be selected in = 3C1 = 3ways

Now 2 balls of every shade can be arranged rather in 2 methods

Thus 4 balls may be arranged(two of each colorations)

= 3x2 = 6ways

Hence general range of arrangements = 18+6 =24 methods.

Question 33. In How Many Different Ways Can Four Books A, B, C And D Be Arranged One Above Another In A Vertical Order Such That The Books A And B Are Never In Continuous Position?

Answer :

The number of association in which A and B are not together

= Total wide variety of arrangements

= Number of preparations in which A and B are collectively =four!-three!X2! = 24-12 =12.

SAP Aptitude Interview Questions

Question 34. 20% Of 40 + ? % Of 80 = one hundred twenty?

Answer :

20% of forty + ? % of 80 = 120

=> 800/100 + ?/one hundred * eighty = one hundred twenty

=> ? = one hundred forty.