Question 1. Two Trains A And B Start Running Together From The Same Point In The Same Direction At 60kmph And 72kmph Respectively. If The Length Of Each Train Is 240m. How Long Will It Take For The Train B To Cross Train A?

Answer :

Relative velocity =(seventy two -60)kmph

= 12kmph = (12 x five/18)m/sec = 10/three m/sec

Total distance blanketed =(240 +240)m =480m

Required time =(480 x three/10)sec = 144sec = 2min 24 sec.

Question 2. Two Trains 105m And 90m Long Run At The Speeds Of forty five Kmph And 72 Kmph Respectively In Opposite Direction On Parallel Tracks. The Time Which They Take To Cross Each Other Is?

Answer :

Sum of the lengths of the trains = (one hundred and five + 90)m = 195m

Relative velocity = (seventy two +45)kmph

= 117kmph =(117 x 5/18)m/sec = 585/18 m/sec

Required Time = (195 x 18/585)sec = 6 Sec.

Aptitude Interview Questions

Question three. A Train Crosses A Pole In 15 Seconds While It Crosses A 100m Long Platform In 25 Seconds. The Length Of The Train Is?

Answer :

Let the period of the educate be x meters.

Then x/15 = (a hundred+x)/25

=> 25x = 1500 + 15x

=> 10x = 1500

=> x =one hundred fifty.

Hence the lengths of the trains is 150m.

Question 4. A Train Travelling At Constant Speed Crosses A 96m Long Platform In 12 Seconds And Another 141m Long Platform In 15 Seconds. The Length Of The Train And It’s Speed Are?

Answer :

Let the length of the teach be x metres.

=>(96+x)/12=(141+x)/15

=> 15x(96 +x) = 12 x (141 + x)

=> 3x = (1692 -1440) = 252

=> X = 84m

Speed of the teach = 15 m/sec

= (15 x 18/5)kmph = 54kmph.

Question five. A Metal Sheet 27 Cm Long 8cm Broad And 1 Cm Thick Is Melted Into A Cube. The Difference Between The Surface Areas Of Two Solids Is?

Answer :

Volume of sheet = (27 × 8 × 1)cm3 = 216 cm3

Volume of cube fashioned = 216 cm3

Therefore, Edge of the cube = (6 × 6 × 6)1/3 = 6 cm

Surface place of unique cuboid = 2 (27 × 8 + eight × 1 + 27 × 1) cm2 = 502 cm2

Surface place of the dice fashioned = [6 × (6) 2] cm2 = 216 cm2

Therefore, Difference in regions = (502 - 216)cm2= 286 cm2.

VMware Aptitude Interview Questions

Question 6. If The Volumes Of Two Cubes Are In The Ratio eight: 1, The Ratio Of Their Edges Is?

Answer :

Volumes be 8x3and x3

2x and x respectively

Therefore, Ratio in their edges = 2 : 1.

Question 7. Mayank Buys Some Candies For Rs 15 A Dozen And An Equal Number Of Different Candies For Rs 12 A Dozen. He Sells All For Rs sixteen.50 A Dozen And Makes A Profit Of Rs one hundred fifty. How Many Dozens Of Candies Did He Buy Altogether?

Answer :

Mayank buys some candies for Rs 15 a dozen and an equal range of various c

et the range of dozens of chocolates he sold of every range be x

Hence total cost = 12x + 15x = 27x

Total promoting charge = sixteen.50*2x = 33x

Profit = 33x - 27x = 6x

Given 6x = a hundred and fifty => x = 25

Hence he sold 50 dozens of candies in general.

Value Labs Aptitude Interview Questions

Question 8. The Ratio Of Vimal's Age And Aruna's Age Is three: five And Sum Of Their Ages Are 80 Years. The Ratio Of Their Ages After 10 Years Will Be?

Answer :

3x + 5x = 80 => x =10

Ratio of their a long time after 10 Years

= (3x +10 : 5x + 10)

= 40 : 60

= 2 : three.

Question nine. Jayesh Is As Much Younger To Anil As He Is Older To Prashant If The Sum Of The Ages Of Anil And Prashant Is 48 Years, What Is The Age Of Jayesh?

Answer :

Anil’s age = x years Prashant’s age = (48 -x)Years

The age of Jayesh be P years

P –(48 -x) = x –p

=> 2P =forty eight

=> P= 24 Years.

Abaxis Aptitude Interview Questions

Question 10. Ratio Of Ashok's Age To Pradeep's Age Is Equal To four: 3. Ashok Will Be 26 Years Old After 6 Years How Old Is Pradeep Now?

Answer :

Ashok’s age = 4x and pradeep’s age =3x years

Therefore, 4x +6 = 26 => x = 5

Pradeep age = 3x = 15 years.

Question 11. Three Years Ago The Average Age Of A And B Was 18 Years With C Joining Them, Then The Average Becomes 22 Years. How Old Is C Now?

Answer :

Sum of ages of A and B, three Years ago =(18 x 2) = 36 Years

Sum of a while of A, B and C,

Now = (22 x 3) = 66 Years

Sum of ages of A and B,

Now = (36 +6)Years = forty two Years

Therefore, C’s age = (sixty six - 42)Years = 24 Years.

Yahoo Aptitude Interview Questions

Question 12. The Sum Of The Ages Of A Father And Son Is forty five Years Five Years Ago The Product Of Their Ages Was four Times The Father's Age At That Time. The Present Ages Of The Father And Son Respectively Are?

Answer :

Present a while of father and son be x years and (45-x) years

(x -5)(forty five –x -five) = four(x -five)

-x2 +41x -one hundred eighty =0 or x =36.

Therefore, gift a long time of dad and son are 36 years and 9 years.

Aptitude Interview Questions

Question 13. The Age Of Arvind's Father Is 4 Times His Age If 5 Years Ago Father’s Age Was 7 Times Of The Age Of His Son At The Time. What Is Arvind's Father’s Present Age?

Answer :

Arvind’s age be x years Father’s age = 4x years.

Therefore (4x -5) =7(x -five) or 3x = 30

=> x =10

Arvind’s father’s age is forty years.

Question 14. 10 Years Ago, Chandravati’s Mother Was 4 Times Older Than Her Daughter, After 10 Years The Mother Will Be Twice Older Than The Daughter. The Present Age Of Chandravati Is?

Answer :

Chandravati’s age 10 years ago be x years

Mother’s age 10 years in the past =(4x)years

2(x +20) = (4x +20)

=> x =10

Present age of Chandravati = (x +10) = two decades.

Question 15. Kamala Got Married 6 Years Ago, Today Her Age Is 1 ¼ Times Her Age At The Time Of Marriage. Her Son’s Age Is (1/10) Times Her Age. Her Son’s Age Is?

Answer :

Kamala’s age 6 years in the past be x years

Kamala’s present age =(x +6) years

Therefore x +6 = 5/four x or 4x + 24 =5x or x =24

Kamala’s present age = 30 years

Son’s present age = (1/10 x 30) = three years.

Yash Technologies Aptitude Interview Questions

Question 16. The Tank Full Of Petrol In Arun’s Motorcycle Lasts For 10 Days, If He Starts Using 25% More Every Day For How Many Days Will The Tank Full Of Petrol Last?

Answer :

Let us expect that Arun uses X devices of petrol regular.

So the amount of petrol in the tank while it's miles fuel might be 10X.

If he started out using 25% more petrol every day, then the amount of petrol he how uses regular may be

X (1 +25/100) =1.25x

Therefore, range of days his petrol will how final = Amount of petrol in tank / amount of petrol used everyday = 10x/1.25x = 10/1.25 = eight Days.

Question 17. If Mohan While Selling Two Goats At The Same Price Makes A Profit Of 10% On One Goat And Suffers A Loss Of 10% On The Other, He?

Answer :

Let SP of every goat be Rs. X

On one goat profit earned = 10%

Therefore CP of first goat = Rs. 10X/eleven

On other goat loss befell = 10%

Therefore CP of second goat = Rs. 10X/9

Thus, total CP of goats =(10x/11+10x/9)

Here CP > SP

Therefore loss percentage

= 2x/ninety nine x ninety nine/200x x one hundred% =1%

Suffers a lack of 1%.

Sony India Aptitude Interview Questions

Question 18. In An Examination, Every Candidate Took Physics Or Mathematics Or Both sixty five.8% Took Physics And fifty nine.2% Took Mathematics The Total Number Of Candidates Was 2000. How Many Candidates Took Both Physics And Mathematics?

Answer :

Let x% applicants take both the topics.

Therefore, Percentage of candidates who opted physics = sixty five.8%

And percent of candidates who opted arithmetic = fifty nine.2%

Therefore, x =(65.Eight + fifty nine.2 - 100)%

= (125 -100)% = 25%

Also total wide variety of applicants = 2000

Therefore, Number of applicants who opted both the subjects = 25/100 x 2000 =500.

VMware Aptitude Interview Questions

Question 19. In A Survey It Was Found That eighty% Of Those Surveyed Owned A Car While 60% Of Those Surveyed Owned A Mobile Phone, If 55% Owned Both A Car And A Mobile Phone, What Percent Of Those Surveyed Owned A Car Or A Mobile Phone Or Both?

Answer :

Given that percentage of automobile proprietors = eighty%

Percentage of mobile cellphone owners = 60%

Percentage of humans having each car and mobile cellphone = 55%

Percentage of people having handiest vehicle = eighty -55 = 25%

Percentage of human beings having only mobile phone = 60 -55 =five%

Percentage of humans having car or cellular phone or both = fifty five% + 25% + five% = 85%.

Question 20. A Gardener Increases The Area Of His Rectangular Garden By Increasing Its Length By forty% And Decreasing By 20%. The Area Of The New Garden?

Answer :

Let the duration and breadth of garden be l and b respectively

Therefore, Area = l x b

New period after forty % increase = l x a hundred and forty/a hundred = 1.4%

New breadth after 20% decrease = b x eighty/a hundred =0.8b

New area = 1.Forty one x 0.8b = 1.12lb

Therefore, trade in area percent =1.12ib-ib/ib*a hundred%= 12% growth (New vicinity – unique area = 0.12> 0 i.E.., Increase).

Intuit Aptitude Interview Questions

Question 21. Candidates In A Competitive Examination Consisted Of 60% Men And 40% Women 70% Men And 75% Women Cleared The Qualifying Test And Entered The Final Test Where eighty% Men And 70% Women Were Successful? Which Of The Following Statements Is Correct?

Answer :

Let there are a hundred people in which 60 guys and forty girls number of guys who cleared the qualifying test

= 70 x 60/a hundred = forty two

Number of girls who cleared the qualifying test

= 40 x ¾ = 30

Number of guys who get success in very last take a look at

= forty two x 4/five = 33.6

Number of girls who get success in final check

= 30 x 70/a hundred = 21

Hence more men cleared the examination than a lady.

Question 22. In A Test A Candidate Attempted Only eight Questions And Secured 50% Marks In Each Of The Questions If The Obtained A Total Of 40% In The Test And All Questions In The Test Carried Equal Marks, How Many Questions Were There In The Test?

Answer :

Let the marks of each query be 10

Total marks got by using the candidate = 8 x five =forty marks

40% = 40 : one hundred = a hundred

Therefore, Total wide variety of questions = 100/10 =10.

Question 23. A City Has A Population Of 300000 Out Of Which 180000 Are Males 50% Of The Population Is Illiterate If 70 % Of The Males Are Literate, Then The Number Of Literate Females Is?

Answer :

Total population = 300000

Total range of males = 180000

Total literates = 5% of overall population = 150000

Number of literate men = 70% of men = 126000.

Capgemini Aptitude Interview Questions

Question 24. In A Company, 60% Of The Employees Are Men, Of This 40 % Are Drawing More Than Rs. 50000 Per Year. 36% Of The Total Employees Of The Company Draw More Than Rs.50000 Per Year Then What Is The Percentage Of Women Who Are Drawing Less Than Rs. 5000 Per Year?

Answer :

Total range of employees be a hundred

Then wide variety of men = 6000/100 = 60

Number of girls = 4000/100 = 40

Therefore, variety of men drawing extra than Rs. 50000 = 2400/100 = 24 guys

Since the variety of overall personnel drawing greater than Rs. 50000 = 3600/a hundred = 36

Number of ladies who draw extra than Rs. 50000 = 36- 24 = 12

Number of girls who draw less than Rs. 50000 = 40 -12 = 28

Therefore, Percentage of the women who draw much less than Rs. 50000 according to yr = 28/forty x 100% = 70%.

Value Labs Aptitude Interview Questions

Question 25. 10 % Of The Electorate Did Not Cast Their Votes In An Election Between Two Candidates. 10 % Of The Votes Polled Were Found Invalid. The Successful Candidate Got 54 % Of The Valid Votes And Won By A Majority Of 1620 Votes. The Number Of Voters Enrolled On The Voter's List Was?

Answer :

Let the wide variety of votes enrolled be x

Votes solid = (ninety/100 × x) = 9x/10

Valid votes = 90% of 9x/10 = (ninety/100 × 9x/10) = 81x/a hundred

Votes polled with the aid of a hit candidate

= (54/a hundred × 81x/a hundred) = 4374x/ten thousand

Votes polled by defeated candidate

= (forty six/100 × 81x/a hundred) = 3726x/10000

=> 4374x – 3726x = 16200000

=> x = 16200000/648 = 25000.

Question 26. The Price Of A Certain Item Is Increased By 15 %. If A Consumer Wants To Keep His Expenditure On The Item Same As Before How Much Percent Must He Reduce His Consumption Of That Item?

Answer :

Reduction % in consumption

= r/(one hundred+r) ×a hundred % =(15/one hundred fifteen × one hundred)%

= three hundred/23 % = 13 1/23 %.

Cognizant Aptitude Interview Questions

Question 27. Find The Roots Of Quadratic Equation: 2x2+ 5x + 2 = zero?

Answer :

2x2+ 4x + x + 2 = zero

2x(x + 2) + 1(x + 2) = 0

(x + 2)(2x + 1) = zero => x = -2, -half.

Abaxis Aptitude Interview Questions

Question 28. Find The Roots Of Quadratic Equation: X2+x - forty two = zero?

Answer :

x2 + 7x - 6x + forty two = zero

x(x + 7) - 6(x + 7) = 0

(x + 7)(x - 6) = 0 => x = -7, 6.

Question 29. The Length Of A Rectangle Is Two - Fifths Of The Radius Of A Circle. The Radius Of The Circle Is Equal To The Side Of The Square, Whose Area Is 1225 Sq.Gadgets. What Is The Area (in Sq.Devices) Of The Rectangle If The Rectangle If The Breadth Is 10 Units?

Answer :

Given that the area of the square = 1225 sq.Gadgets

=> Side of square = v1225 = 35 units

The radius of the circle = side of the square = 35 devices Length of the rectangle = 2/five * 35 = 14 units

Given that breadth = 10 devices

Area of the rectangle = lb = 14 * 10 = one hundred forty sq.Gadgets.

Question 30. The Sector Of A Circle Has Radius Of 21 Cm And Central Angle 135o. Find Its Perimeter?

Answer :

Perimeter of the arena = duration of the arc + 2(radius)

= (one hundred thirty five/360 * 2 * 22/7 * 21) + 2(21)

= 49.5 + 42 = ninety one.5 cm.

Question 31. The Probability That A Speaks Truth Is three/5 And That Of B Speaking Truth Is 4/7. What Is The Probability That They Agree In Stating The Same Fact?

Answer :

If each agree stating the identical reality, both both of them speak reality of both speak fake.

Probability = 3/5 * 4/7 + 2/5 * three/7

= 12/35 + 6/35 = 18/35.

Question 32. From A Pack Of Cards Two Cards Are Drawn One After The Other, With Replacement. The Probability That The First Is A Red Card And The Second Is A King Is -?

Answer :

Let E1 be the event of drawing a crimson card.

Let E2 be the event of drawing a king .

P(E1 n E2) = P(E1) . P(E2)

(As E1 and E2 are impartial)

= half of * 1/thirteen = 1/26.

Question 33. What Is The Probability That A Leap Year Has 53 Sundays And fifty two Mondays?

Answer :

A soar year has 52 weeks and days

Total quantity of instances = 7

Number of favourable cases = 1

i.E., Saturday, Sunday

Required Probability = 1/7.

Yahoo Aptitude Interview Questions

Question 34. 10 Books Are Placed At Random In A Shelf. The Probability That A Pair Of Books Will Always Be Together Is -?

Answer :

10 books can be rearranged in 10! Ways don't forget the 2 books taken as a pair then wide variety of favourable approaches of getting those two books together is 9! 2! Required opportunity = 1/five.