Question 1. Bombay Express Left Delhi For Bombay At 14.30 Hours. Travelling At A Speed Of 60kmph And Rajadhani Express Left Delhi For Bombay On The Same Day At 16.30 Hours Travelling Speed Of 80kmph. How Far Away From Delhi Will The Two Trains Meet?

Answer :

Let the educate meet at a distance of x km from Delhi.

Then x/60 –x/80 = 2

=> 4x -3x

=> x =480

Therefore, Required distance = 480km.

Question 2. R And S Start Walking Towards Each Other At 10 Am At Speeds Of 3km/hr And 4km/hr Respectively. They Were Initially 17.5km Apart At What Time Do They Meet?

Answer :

Suppose they meet after x hours , then 3x +4x = 17.Five

=> 7x = 17.Five

=> X = 2.5hours

So they meet at 12: 30 p.M.

Aptitude Interview Questions

Question three. A Certain Distance Covered At A Certain Speed. If Half Of This Distance Is Covered In Double The Time The Ratio Of The Two Speeds Is?

Answer :

Let x kms be blanketed in y hours, then first pace = x / y km/hr

Again x/2 km is included in 2y hrs

Therefore, new velocity = (x/2 x 1/2y)km/hr

= (x/ 4y) km/hr

Ratio of speeds = x/y : x/4y = 1 : ¼

= four : 1.

Question four. The Speeds Of A And B Are In The Ratio three: 4. A Takes 20 Minutes More Than B To Reach A Destination. In What Time Does A Reach The Destination?Let The Time Taken By A Be X Hours?

Answer :

The time taken by B =(x-20/60)hrs = (x-1/3)hrs

Ratio of speeds = Inverse ratio of time taken

Therefore three: four =(x-1/3) : x

=>3x-1/3x=3/4

=> 12x -4 =9x

=> 3x =four

=> X=four/three hrs.

X=1 1/three hours.

Required time = 1 1/three hrs.

Question 5. The Ratio Between The Speed Of Two Trains Is 7: eight.If The Second Train Runs 400km In five Hours. The Speed Of The First Train Is?

Answer :

Let the velocity of the first train be 7x km/hr

Then the speed of the second one train is 8x km/hr

But speed of the second one teach = four hundred/five km/hr = 80km/hr

=> 8x =eighty

=> X=10

Hence the speed of first educate is (7 x 10)km/hr = 70km/hr.

HR Interview Questions

Question 6. Two Trains Approach Each Other At 30 Km/hr And 27km/hr From Two Places 342km Apart After How Many Hours Will They Meet?

Answer :

Suppose the 2 trains meet after x hours, then

=> 30x + 27x = 342

=> 57x = 342

=> X = 6

So the two trains will meet after 6 hours.

Question 7. A Can Do (1/three) Of A Work In 5 Days And B Can Do (2/5) Of The Work In 10 Days. In How Many Days Both A And B Together Can Do The Work?

Answer :

1/three of labor is carried out by using A in five days

Therefore, whole paintings can be carried out with the aid of A in 15 days

2/5 of work is finished by means of B in 10 days

Whole work could be accomplished through B in (10 x 5/2) i.E.., 25 days

Therefore (A + B)’s 1 day’s paintings = (1/15 + 1/25) = eight/seventy five

So each together can finish seventy five/8 days i.E.., nine 3/8 days.

Value Labs Aptitude Interview Questions

Question eight. A, B And C Contract A Work For Rs. 550. Together A And B Are To Do 7/11 Of The Work. The Share Of C Should Be?

Answer :

Work to be completed by using C = (1 – 7/eleven) = 4/11

Therefore, (A +B) = C = 7/11 : 4/11 = 7 : four

Therefore C’s percentage = Rs.(550 x four/11) = Rs. 2 hundred.

Question 9. A Can Do A Piece Of Work In 80 Days. He Works At It For 10 Days And Then B Alone Finishes The Work In 42 Days. The Two Together Could Complete The Work In?

Answer :

A’s 10 days work = (10 x 1/eighty) = 1/eight

Remaining paintings = (1 -1/eight) = 7/eight

Therefore 7/8 paintings is finished through A in forty two days.

Whole paintings will be accomplished by using A in (42 x eight/7)i.E.., 48 days

Therefore, (A+ B)’s 1 day paintings = (1/80 + 1/48) = 8/240 = 1/30.

A and B collectively can end it in 30days.

Abaxis Aptitude Interview Questions

Question 10. Mahesh And Umesh Can Complete A Work In 10 Days And 15 Days Respectively. Umesh Starts The Work And After 5 Days Mahesh Also Joins Him In All The Work Would Be Completed In?

Answer :

Umesh’s five day’s paintings = five x 1/15 = 1/3

Remaining work = (1 – 1/3) = 2/three (1/10 +1/ 15) paintings is accomplished through each in 1 day

Therefore 2/three work is performed by means of both in (6 x 2/three) = 4days.

The work turned into finished in 9 days.

Question 11. Twelve Men Can Complete A Work In eight Days. Three Days After They Started The Work, three More Men Joined Them. In How Many Days Will All Of Them Together Complete Remaining Work?

Answer :

1 guy’s one day’s work = 1/ninety six 12 guys’s 3 day’s work = (three x 1/8) = three/eight

Remaining work = (1 – 3/8) = five/8 15 guys’s 1 day’s paintings = 15/96

Now 15/ninety six paintings is finished through them in 1day

Therefore five/eight paintings will be executed via them in (ninety six/15 x 5/eight) i.E., four days.

Zensar Technologies Aptitude Interview Questions

Question 12. A Is 30% More Efficient Than B. How Much Time Will They, Working Together, Take To Complete A Job Which A Alone Could Have Done In 23 Days?

Answer :

Ratio of instances taken through A and B = a hundred:a hundred thirty = 10:thirteen

Suppose B takes x days to do the paintings.

X = (23 * 13)/10 = 299/10

A's 1 day work = 1/23; B's 1 day work = 10/299

(A + B)'s 1 day work = (1/23 + 10/299) = 1/thirteen

A and B together can complete the job in 13 days.

Aptitude Interview Questions

Question thirteen. A Can Finish A Work In 18 Days B Can Do The Same Work In 15 Days. B Worked For 10 Days And Left The Job. In How Many Days, A Alone Can Finish The Remaining Work?

Answer :

B's 10 day's work = 1/15 * 10 = 2/3

Remaining paintings = (1 - 2/3) = 1/3

Now, 1/18 work is done by way of A in 1 day.

1/3 work is done through A in (18 * 1/3) = 6 days.

Question 14. A Can Do A Price Of Work In 30days While B Can Do It In 40 Days. In How Many Days Can A And B Working Together Do It?

Answer :

(A +B)’s 1 day’s work = (1/30 + 1/40) = 7/one hundred twenty

Time is taken through each to complete the work = one hundred twenty/7 days

= 17 1/7 days.

Question 15. X Varies Inversely As Square Of Y. Given That Y = 2 For X = 1. The Value Of X For Y = 6 Will Be Equal To?

Answer :

Given x = okay/y2, wherein okay is a consistent.

Now, y = 2 and x = 1 gives ok = four.

X = four/y2 => x = four/62, whilst

y = 6 => x = 4/36 = 1/nine.

Yash Technologies Aptitude Interview Questions

Question 16. Megha Purchased a hundred and twenty Calendars At A Rate Of Rs 3 Each And Sold 1/three Of Them At The Rate Of Rs. Four Each. 1/2 Of Them At The Rate Of Rs five Each And Rest At The Cost Price. Her Profit Per Cent Was?

Answer :

CP of a hundred and twenty calendars = 120 x 3 = Rs. 360

SP of forty at Rs. Four each = Rs. 40 x four = Rs.A hundred and sixty

SP of 60 at Rs five each = Rs 60 x 5 = Rs. 300

SP of closing 20 calendars = Rs 20 x 3 = 60

Total SP = Rs.( one hundred sixty + 300 + 60) = 520

Profit % = 520 – 360 = a hundred and sixty

Profit % = a hundred and sixty/360 x one hundred = four hundred/nine.

Question 17. The Ratio Of The Number Of Boys And Girls In A College Is 7:8. If The Percentage Increase In The Number Of Boys And Girls Be 20% And 10% Respectively. What Will Be The New Ratio?

Answer :

Originally, let the range of boys and ladies in the college be 7x and 8x respectively.

Their accelerated wide variety is (a hundred and twenty% of 7x) and (110% of 8x).

I.E., (a hundred and twenty/a hundred * 7x) and (one hundred ten/100 * 8x)

i.E., 42x/five and 44x/five

Required ratio = 42x/5 : 44x/5 = 21:22.

Oracle Aptitude Interview Questions

Question 18. A Sum Of Money Is To Be Distributed Among A, B, C, D In The Proportion Of five:2:four:three. If C Gets Rs. One thousand More Than D, What Is B's Share?

Answer :

Let the shares of A, B, C and D be 5x, 2x, 4x and 3x Rs. Respectively.

Then, 4x - 3x = one thousand => x = one thousand.

B's proportion = Rs. 2x = 2 * 1000 = Rs. 2000.

HR Interview Questions

Question 19. If forty% Of A Number Is Equal To Two-1/3 Of Another Number, What Is The Ratio Of First Number To The Second Number?

Answer :

Let 40% of A = 2/3 B. Then,

40A/a hundred = 2B/three => 2A/five = 2B/three

A/B = (2/3 * five/2) = five/3

A:B = five:three.

Question 20. Ratio Of The Earnings Of A And B Is four:7. If The Earnings Of A Increases By 50% And Those Of B Decreased By 25%, The New Ratio Of Their Earnings Becomes 8:7. What Are A's Earnings?

Answer :

Let the authentic income of A and B be Rs. 4x and Rs. 7x.

New profits of A = one hundred fifty% 0f Rs. 4x = (a hundred and fifty/one hundred * 4x) = Rs. 6x

New profits of B = seventy five% of Rs. 7x = (seventy five/a hundred * 7x) = Rs. 21x/four

6x:21x/four = 8:7

This does now not provide x. So, the given facts is inadequate.

Sony India Aptitude Interview Questions

Question 21. Salaries Of Ravi And Sumit Are In The Ratio 2:3. If The Salary Of Each Is Increased By Rs. 4000, The New Ratio Becomes forty:fifty seven. What Is Sumit's Present Salary?

Answer :

Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively.

Then, (2x + 4000)/(3x + 4000) = forty/fifty seven

6x = 68000 => 3x = 34000

Sumit's gift earnings = (3x + 4000) = 34000 + 4000 = Rs. 38,000.

Question 22. If Rs. 510 Be Divided Among A, B, C In Such A Way That A Gets 2/three Of What B Gets And B Gets 1/four Of What C Gets, Then Their Shares Are Respectively?

Answer :

(A = 2/3 B and B = 1/4 C) = A/B = 2/three and B/C = 1/4

A:B = 2:three and B:C = 1:four = 3:12

A:B:C = 2:three:12

A;s percentage = 510 * 2/17 = Rs. 60

B's percentage = 510 * 3/17 = Rs. Ninety

C's percentage = 510 * 12/17 = Rs. 360.

Question 23. In Covering Distance, The Speed Of A & B Are In The Ratio Of three:four.A Takes 30min More Than B To Reach The Destination. The Time Taken By A To Reach The Destination Is?

Answer :

Ratio of speed = 3:four

Ratio of time = 4:3

permit A takes 4x hrs, B takes 3x hrs

then 4x-3x = 30/60 hr

x = ½ hr

Time taken by way of A to reach the destination is 4x = four * ½ = 2 hr.

TCS Aptitude Interview Questions

Question 24. Seats For Mathematics, Physics And Biology In A School Are In The Ratio five:7:8. There Is A Proposal To Increase These Seats By 40%, 50% And seventy five% Respectively. What Will Be The Ratio Of Increased Seats?

Answer :

Originally, allow the range of seats for Mathematics, Physics and Biology be 5x, 7x and 8x respectively. Number of elevated sears are (a hundred and forty% of 5x), (a hundred and fifty% of 7x) and (one hundred seventy five% of 8x)

i.E., (140/a hundred * 5x), (150/a hundred * 7x) and (a hundred seventy five/one hundred * 8x)

i.E., 7x, 21x/2 and 14x

Required ratio = 7x:21x/2:14x

= 14x : 21x : 28x = 2:3:4.

Value Labs Aptitude Interview Questions

Question 25. A Person Invests Money In Three Different Schemes For 6 Years, 10 Years And 12 Years At 10 %, 12 %, And 15 %. Simple Interest Respectively. At The Completion Of Each Scheme, He Gets The Same Interest. The Ratio Of His Investments Is?

Answer :

Let the desired ratio be x: 1: y.

Then S.I on Rs x for 6 years at 10% p.A = S.I on re.1 10 years at 12 %p.A

X × 10/one hundred × 6 = 1 × 12/100 × 10

=> X = a hundred and twenty/60 =2

S.I on Re.1 for 10 years at 12 % p.A = S. I on Rs. Y for 12 years at 15 % p.A

Therefore, (1 x 12/a hundred x 10) = (y x 15/a hundred x 12)

=> y = a hundred and twenty/180 = 2/3

Required ratio = 2 : 1 = 2/three = 6 : three : 2.

Question 26. Simple Interest On Rs.500 For four Years At 6.25 % Per Annum Is Equal To The Simple Interest On Rs. 400 At five % Per Annum For A Certain Period Of Time. The Period Of Time Is?

Answer :

Let the desired period of time be x years.

Then 500 x 4 x 6.25/100 = four hundred x 5/100 × x

=> 20 x 6.25 = 20 × x

=> X = 6.25 = 625/a hundred = 25/four = 6 ¼ years.

Cognizant Aptitude Interview Questions

Question 27. A Borrows Rs.800 At The Rate Of 12 % Per Annum. Simple Interest And B Borrows Rs.910 At The Rate Of 10 % Per Annum Simple Interest. In How Many Years Will Their Amounts At Debts Be Equal?

Answer :

Let the desired time be x years.

Then 800 + 800 x 12/one hundred × x = 910 + 910 x 10/one hundred × x

=> (96x -ninety one x) = 110

=> 5x =110

=> x =22.

Abaxis Aptitude Interview Questions

Question 28. Rs.6000 Becomes Rs.7200 In four Years At A Certain Rate Of Interest. If The Rate Becomes 1.5 Times Of Itself. The Amount Of The Same Principle In 5 Years Will Be?

Answer :

S.I on Rs. 600 for 4 Years = Rs (7200 - six hundred) = Rs 1200

Therefore Rate = (120000/24000) % p.A = 5 % p.A

New Rate = (5 x three/2) % = 15/2 % p.A

Required Amount = [6000 + (6000 x 5/100 x 15/2)]

= Rs(6000 + 2250) = Rs 8250.

Question 29. Kruti Took A Loan At Simple Interest At 6 % In The First Year With An Increase Of 0.5 % In Each Subsequent Year. She Paid Rs. 3375 As Interest After four Years. How Much Loan Did She Take?

Answer :

Let the mortgage taken be Rs. X , then

X × 6/one hundred × 1 + X × 6.Five/100 × 1 + X × 7/100 × 1 + X × 7.Five/a hundred × 1 = 3375

=> (6+ 6.5 +7 +7.5) × X/a hundred = 3375

=> X = (3375 × one hundred/27) = 12500.

MindTree Aptitude Interview Questions

Question 30. The Captain Of A Cricket Team Of 11 Members Is 26 Years Old And The Wicket Keeper Is 3 Years Older. If The Ages Of These Two Are Excluded, The Average Age Of The Remaining Players Is One Year Less Than The Average Age Of The Whole Team. What Is The Average Of The Team?

Answer :

Let the common of the whole crew be x years.

11x - (26 + 29) = 9(x - 1)

= 11x - 9x = 46

= 2x = 46 => x = 23

So, average age of the crew is 23 years.

Question 31. A Cricketer Has A Certain Average For 10 Innings. In The Eleventh Inning, He Scored 108 Runs, There By Increasing His Average By 6 Runs. His New Average Is?

Answer :

Let common for 10 innings be x. Then,

(10x + 108)/eleven = x + 6

= 11x + 66 = 10x + 108

= x = 42.

New common = (x + 6) = forty eight runs.

Question 32. A Cricketer Whose Bowling Average Is 12.Four Runs Per Wicket Takes 5 Wickets For 26 Runs And There By Decreases His Average By 0.Four. The Number Age Of The Family Now Is?

Answer :

Let the number of wickets taken until the ultimate in shape be x. Then,

(12.4x + 26)/(x + five) = 12

= 12.4x + 26 = 12x + 60

= 0.4x = 34

= x = 340/4 = eighty five.

Question 33. The Average Monthly Income Of P And Q Is Rs. 5050. The Average Monthly Income Of Q And R Is 6250 And The Average Monthly Income Of P And R Is Rs. 5200. The Monthly Income Of P Is?

Answer :

Let P, Q and R constitute their respective month-to-month earning.

Then, we've got:

P + Q = (5050 * 2) = 10100 --- (i)

Q + R = (6250 * 2) = 12500 --- (ii)

P + R = (5200 * 2) = 10400 --- (iii)

Adding (i), (ii) and (iii), we get:

2(P + Q + R) = 33000 = P + Q + R = 16500 --- (iv)

Subtracting (ii) from (iv), we get, P = 4000.

P's month-to-month earnings = Rs. 4000.

Zensar Technologies Aptitude Interview Questions

Question 34. The Average Weight Of A, B And C Is 45 Kg. If The Average Weight Of A And B Be forty Kg And That Of B And C Be 43 Kg, Then The Weight Of B Is?

Answer :

Let A, B, C constitute their respective weights.

Then, we've:

A + B + C = (forty five * 3) = one hundred thirty five --- (i)

A + B = (forty * 2) = 80 --- (ii)

B + C = (43 * 2) = 86 --- (iii)

Adding (ii) and (iii),

we get: A + 2B + C = 166 --- (iv)

Subtracting (i) from (iv), we get: B = 31

B's weight = 31 kg.

Question 35. A Man Covers A Distance On Scooter .Had He Moved three Kmph Faster He Would Have Taken 40 Min Less. If He Had Moved 2kmph Slower He Would Have Taken 40 Min More. The Distance Is?

Answer :

Let distance = x m

Usual price = y kmph

x/y ? x/y+3 = forty/60 hr

2y(y+three) = 9x ?????1

x/y-2 ? x/y = 40/60 hr y(y-2) = 3x ??????2

divide 1 & 2 equations

by means of fixing we get x = forty.

Question 36. A Tank Is Filled In five Hours By Three Pipes A, B And C. The Pipe C Is Twice As Fast As B And B Is Twice As Fast As A. How Much Time Will Pipe A Alone Take To Fill The Tank?

Answer :

Suppose pipe A on my own takes x hours to fill the tank.

Then, pipes B and C will take x/2 and x/4 hours respectively to fill the tank.

1/x + 2/x + four/x = 1/five

7/x = 1/five => x = 35 hrs.

Yash Technologies Aptitude Interview Questions

Question 37. A Tank Is Filled By Three Pipes With Uniform Flow. The First Two Pipes Operating Simultaneously Fill The Tank In The Same During Which The Tank Is Filled By The Third Pipe Alone. The Second Pipe Fills The Tank 5 Hours Faster Than The First Pipe And four Hours Slower Than The Third Pipe. The Time Required By The First Pipe Is?

Answer :

Suppose, first pipe alone takes x hours to fill the tank. Then, 2nd and 0.33 pipes will take (x - 5) and (x - 9) hours respectively to fill the tank.

1/x + 1/(x - five) = 1/(x - nine)

(2x - five)(x - nine) = x(x - five)

x2 - 18x + 45 = 0

(x- 15)(x - three) = 0 => x = 15.

Question 38. A Large Tanker Can Be Filled By Two Pipes A And B In 60 And forty Minutes Respectively. How Many Minutes Will It Take To Fill The Tanker From Empty State If B Is Used For Half The Time And A And B Fill It Together For The Other Half?

Answer :

Part filled via (A + B) in 1 minute = (1/60 + 1/forty) = 1/24

Suppose the tank is stuffed in x minutes.

Then, x/2(1/24 + 1/40) = 1

x/2 * 1/15 = 1 => x = 30 min.

Question 39. Two Pipes A And B Can Fill A Tank In 15 Min And 20 Min Respectively. Both The Pipes Are Opened Together But After 4 Min, Pipe A Is Turned Off. What Is The Total Time Required To Fill The Tank?

Answer :

Part stuffed in 4 minutes = 4(1/15 + 1/20) = 7/15

Remaining component = 1 - 7/15 = 8/15

Part stuffed with the aid of B in 1 minute = 1/20

1/20 : eight/15 :: 1 ; x

x = eight/15 * 1 * 20 = 10 2/3 min = 10 min forty sec.

The tank might be full in (4 min. + 10 min. 40 sec) = 14 min forty sec.

Question forty. Two Pipes A And B Together Can Fill A Cistern In 4 Hours. Had They Been Opened Separately, Then B Would Have Taken 6 Hours More Than A To Fill Cistern. How Much Time Will Be Taken By A To Fill The Cistern Separately?

Answer :

Let the cistern be crammed by means of pipe A on my own in x hours.

Then, pipe B will fill it in (x + 6) hours.

1/x + 1/(x + 6) = 1/four

x2 - 2x - 24 = zero

(x - 6)(x + 4) = zero => x = 6.

Oracle Aptitude Interview Questions

Question forty one. The Compound Interest On Rs 16000 For 9 Months At 20% P.A Compounded Quarterly Is?

Answer :

P = Rs 16000, R = (10/2)%

according to area, t = 3 quarters

C.I = Rs [16000 × (1+ 5/one hundred)three-16000)

= Rs [16000 × 21/20 ×21/20× 21/20- 16000)

=Rs (18522-16000)=Rs 2522.

Question forty two. If The Interest Is Payable Annually Than The Principal On Which The Compound Interest For 3 Years At 10% P.A Is Rs 33/- Is Given By?

Answer :

Let the principal be Rs x.

Then X × (1 + 10/a hundred)three – x = 331

=> (x × eleven/10 × eleven/10 × 11/10 - x) = 331

=> ((1331x-1000x)/a thousand) = 331

=> 331x = 331000

=> X = a thousand

Hence the major is Rs a thousand.

Sony India Aptitude Interview Questions

Question 43. If The Rate Of Interest Be four% Per Annum For First Year 5% Per Annum For The Second Year And 6% Per Annum From The Third Year Then The Compound Interest Of Rs 10000 For 3 Years Will Be?

Answer :

Amount = Rs[10000 × (1 + 4/100) × (1 +5/100) × (1 × 6/100)]

= Rs(1000 × 26/25 × 21/20 × 53/50)

= Rs (57876/5) = Rs 11575.20

C.I = Rs (11575.20 - ten thousand) = Rs 1575.20.

Question 44. Subhash Purchased A Tape Recorder At nine/10th Of Its Selling Price And Sold It At 8% More Than Its S.P. His Gain Is?

Answer :

S.P be Rs. X C.P paid by means of Subhash = Rs. 9X/10

S.P acquired by means of Subhash = Rs. (108% of Rs. X)

= Rs. 27X/25

Gain = Rs. (27X/25 – 9X/10)

= Rs. 9X/50 Gain = (9X/50 × 10/9X × one hundred)% = 20%.

Question forty five. The Ratio Of The Prices Of Three Different Types Of Cars Is 4:five:7. If The Difference Between The Costliest And The Cheapest Cars Is Rs. 60000 The Price Of The Car Of Modest Price Is?

Answer :

Let the expenses be 4X, 5X and seven X rupees

7X – 4X = 60000

=> X = 20000

Required price = 5X = Rs. A hundred thousand.

Question forty six. A Discount Series Of 10%, 20% And forty% Is Equal To A Single Discount Of?

Answer :

Original price = Rs. A hundred

Price after first discount = Rs. Ninety

Price after 2nd bargain = Rs. (80/a hundred × ninety) = Rs. 72

Price after 1/3 cut price = Rs. (60/100 × 72) = Rs. 43.20

Single bargain = (100 – 43.20) = fifty six.8%.

Question forty seven. Kabir Buys An Article With 25% Discount On Its Marked Price. He Makes A Profit Of 10 % By Selling It At Rs. 660. The Marked Price Is?

Answer :

Original fee be Rs. X

C.P = (X – 25% of X) = 3X/4

S.P = (3X/4 + 10% of 3X/4) = 33X/40= 660

=> X = 800.